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Oracle PL/SQL Developer Certified Associate 1z0-071 來吧，你將是未來最棒的IT專家。
Oracle PL/SQL Developer Certified Associate 1z0-071考題 - Oracle Database SQL Goldmile-Infobiz是領先于世界的學習資料提供商之一，您可以下載我們最新的PDF版本免費試用作為體驗。 一生輾轉千萬裏，莫問成敗重幾許，得之坦然，失之淡然，與其在別人的輝煌裏仰望，不如親手點亮自己的心燈，揚帆遠航。Goldmile-Infobiz Oracle的1z0-071 學習資料考試培訓資料將是你成就輝煌的第一步，有了它，你一定會通過眾多人都覺得艱難無比的Oracle的1z0-071 學習資料考試認證，獲得了這個認證，你就可以在你人生中點亮你的心燈，開始你新的旅程，展翅翱翔，成就輝煌人生。
現在IT行业競爭越來越激烈，通過Oracle 1z0-071考題認證考試可以有效的帮助你在现在这个竞争激烈的IT行业中稳固和提升自己的地位。在我們Goldmile-Infobiz中你可以獲得關Oracle 1z0-071考題認證考試的培訓工具。我們Goldmile-Infobiz的IT精英團隊會及時為你提供準確以及詳細的關Oracle 1z0-071考題認證考試的培訓材料。
Oracle 1z0-071考題 - 這是通過考試最快的捷徑了。
如果你還在為了通過Oracle 1z0-071考題認證考試苦苦掙扎地奮鬥，此時此刻Goldmile-Infobiz可以給你排憂解難。Goldmile-Infobiz能為你提供品質好的培訓資料來幫助你考試，讓你成為一名優秀的Oracle 1z0-071考題的認證會員。如果你已經決定通過Oracle 1z0-071考題的認證考試來提升自己，那麼選擇我們的Goldmile-Infobiz是不會有錯的。我們的Goldmile-Infobiz能承諾，一定讓你成功地通過你第一次參加的Oracle 1z0-071考題認證考試，拿到Oracle 1z0-071考題認證證來提升和改變自己。
在這裏我想說的就是怎樣才能更有效率地準備1z0-071考題考試，並且一次就通過考試拿到考試的認證資格。Oracle的認證考試現在是很有人氣的考試。
1z0-071 PDF DEMO:
QUESTION NO: 1
View the Exhibit and examine the details of PRODUCT_INFORMATION table.
You have the requirement to display PRODUCT_NAME from the table where the CATEGORY_ID column has values 12 or 13, and the SUPPLIER_ID column has the value 102088. You executed the following SQL statement:
SELECT product_name
FROM product_information
WHERE (category_id = 12 AND category_id = 13) AND supplier_id = 102088; Which statement is true regarding the execution of the query?
A. It would execute but the output would return no rows.
B. It would not execute because the same column has been used in both sides of the AND logical operator to form the condition.
C. It would not execute because the entire WHERE clause condition is not enclosed within the parentheses.
D. It would execute and the output would display the desired result.
Answer: A
QUESTION NO: 2
Examine the structure of the MEMBERS table:
NameNull?Type
------------------ --------------- ------------------------------
MEMBER_IDNOT NULLVARCHAR2 (6)
FIRST_NAMEVARCHAR2 (50)
LAST_NAMENOT NULLVARCHAR2 (50)
ADDRESSVARCHAR2 (50)
You execute the SQL statement:
SQL > SELECT member_id, ' ' , first_name, ' ' , last_name "ID FIRSTNAME LASTNAME " FROM members; What is the outcome?
A. It fails because the alias name specified after the column names is invalid.
B. It executes successfully and displays the column details in three separate columns and replaces only the last column heading with the alias.
C. It executes successfully and displays the column details in a single column with only the alias column heading.
D. It fails because the space specified in single quotation marks after the first two column names is invalid.
Answer: B
QUESTION NO: 3
Examine the description of the EMP_DETAILS table given below:
Which two statements are true regarding SQL statements that can be executed on the EMP_DETAIL
TABLE?
A. An EMP_IMAGE column can be included in the GROUP BY clause.
B. An EMP_IMAGE column cannot be included in the ORDER BY clause.
C. You cannot add a new column to the table with LONG as the data type.
D. You can alter the table to include the NOT NULL constraint on the EMP_IMAGE column.
Answer: B,C
QUESTION NO: 4
View the Exhibit and examine the structure of the ORDER_ITEMS table.
Examine the following SQL statement:
SELECT order_id, product_id, unit_price
FROM order_items
WHERE unit_price =
(SELECT MAX(unit_price)
FROM order_items
GROUP BY order_id);
You want to display the PRODUCT_ID of the product that has the highest UNIT_PRICE per ORDER_ID.
What correction should be made in the above SQL statement to achieve this?
A. Replace = with the >ANY operator
B. Replace = with the IN operator
C. Remove the GROUP BY clause from the subquery and place it in the main query
D. Replace = with the >ALL operator
Answer: B
QUESTION NO: 5
The PRODUCT_INFORMATION table has a UNIT_PRICE column of data type NUMBER (8, 2).
Evaluate this SQL statement:
SELECT TO_CHAR(unit_price, ' $9,999') FROM product_information;
Which two statements are true about the output?
A. A row whose UNIT_PRICE column contains the value 10235.99 will be displayed as #######.
B. A row whose UNIT_PRICE column contains the value 1023.99 will be displayed as $1,024.
C. A row whose UNIT_PRICE column contains the value 10235.99 will be displayed as $1,023.
D. A row whose UNIT_PRICE column contains the value 1023.99 will be displayed as $1,023.
E. A row whose UNIT_PRICE column contains the value 10235.99 will be displayed as $1,0236.
Answer: A,D
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Updated: May 28, 2022