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QUESTION NO: 1
A switch has 48 ports and 4 VLANs. How many collision and broadcast domains exist on the switch (collision, broadcast)?
A. 4, 48
B. 48, 4
C. 48, 1
D. 1, 48
E. 4, 1
Answer: B
Explanation:
A switch uses a separate collision domain for each port, and each VLAN is a separate broadcast domain.
QUESTION NO: 2
Which IOS command is used to initiate a login into a VTY port on a remote router?
A. router# login
B. router# telnet
C. router# trace
D. router# ping
E. router(config)# line vty 0 5
F. router(config-line)# login
Answer: B
Explanation:
Explanation/Reference:
VTY ports are telnet ports hence command B will initiate login to the telnet port.
QUESTION NO: 3
Refer to the exhibit.
The junior network support staff provided the diagram as a recommended configuration for the first phase of a four-phase network expansion project. The entire network expansion will have over 1000 users on 14 network segments and has been allocated this IP address space.
192.168.1.1 through 192.168.5.255
192.168.100.1 through 192.168.100.255
What are three problems with this design? (Choose three.)
A. The AREA 1 IP address space is inadequate for the number of users.
B. The AREA 3 IP address space is inadequate for the number of users.
C. AREA 2 could use a mask of /25 to conserve IP address space.
D. The network address space that is provided requires a single network-wide mask.
E. The router-to-router connection is wasting address space.
F. The broadcast domain in AREA 1 is too large for IP to function.
Answer: A,C,E
Explanation:
The given IP addresses of areas 1 and 3 along with network masks of 24 cannot accommodate 500 users so are inadequate, while the area 2 is having over capacity so its network mask can be reduced to 25 to accommodate the only 60 users it has.
QUESTION NO: 4
Refer to the exhibit.
Which command would you use to configure a static route on Router1 to network 192.168.202.0/24 with a nondefault administrative distance?
A. router1(config)#ip route 1 192.168.201.1 255.255.255.0 192.168.201.2
B. router1(config)#ip route 192.168.202.0 255.255.255.0 192.168.201.2 1
C. router1(config)#ip route 5 192.168.202.0 255.255.255.0 192.168.201.2
D. router1(config)#ip route 192.168.202.0 255.255.255.0 192.168.201.2 5
Answer: D
Explanation:
Since it has /24 CIDR and it also has a non default administrative distance, the answer has to be option D.
QUESTION NO: 5
Given an IP address of 192.168.1.42 255.255.255.248, what is the subnet address?
A. 192.168.1.8/29
B. 192.168.1.32/27
C. 192.168.1.40/29
D. 192.168.1.16/28
E. 192.168.1.48/29
Answer: C
Explanation:
Explanation/Reference:
248 mask uses 5 bits (1111 1000)
42 IP in binary is (0010 1010)
The base subnet therefore is the lowest binary value that can be written without changing the output of an AND operation of the subnet mask and IP...
1111 1000 AND
0010 1010 equals
0010 1000 - which is .40
/24 is standard class C mask.
Adding the 5 bits from the .248 mask gives /29
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Updated: May 28, 2022