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それに、Ciscoの350-401 - Implementing Cisco Enterprise Network Core Technologies (350-401 ENCOR)試験勉強書の試験の実践経験やテストダンプにも含まれています。 Ciscoの350-401 参考資料のオンラインサービスのスタディガイドを買いたかったら、Goldmile-Infobizを買うのを薦めています。Goldmile-Infobizは同じ作用がある多くのサイトでリーダーとしているサイトで、最も良い品質と最新のトレーニング資料を提供しています。
Goldmile-InfobizのCiscoの350-401試験勉強書問題集を買う前に、一部の問題と解答を無料に試用することができます。そうすると、Goldmile-InfobizのCiscoの350-401試験勉強書トレーニング資料の品質をよく知っています。Goldmile-InfobizのCiscoの350-401試験勉強書問題集は絶対あなたの最良の選択です。
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こうすれば、この問題集を利用して、あなたは勉強の効率を向上させ、十分に350-401試験勉強書試験に準備することができます。もし350-401試験勉強書認定試験を受験したいなら、350-401試験勉強書試験参考書が必要でしょう。
350-401 PDF DEMO:
QUESTION NO: 1
Which statement explains why Type 1 hypervisor is considered more efficient than Type 2 hypervisor?
A. Type 1 hypervisor enables other operating systems to run on it
B. Type 1 hypervisor runs directly on the physical hardware of the host machine without relying on the underlying OS
C. Type 1 hypervisor relics on the existing OS of the host machine to access CPU, memory, storage, and network resources.
D. Type 1 hypervisor is the only type of hypervisor that supports hardware acceleration techniques
Answer: B
Explanation:
There are two types of hypervisors: type 1 and type 2 hypervisor.
In type 1 hypervisor (or native hypervisor), the hypervisor is installed directly on the physical server.
Then instances of an operating system (OS) are installed on the hypervisor. Type 1 hypervisor has direct access to the hardware resources. Therefore they are more efficient than hosted architectures.
Some examples of type 1 hypervisor are VMware vSphere/ESXi, Oracle VM Server, KVM and
Microsoft Hyper-V.
In contrast to type 1 hypervisor, a type 2 hypervisor (or hosted hypervisor) runs on top of an operating system and not the physical hardware directly. A big advantage of Type 2 hypervisors is that management console software is not required.
QUESTION NO: 2
What is the correct EBGP path attribute list, ordered from most preferred to the least preferred, that the BGP best-path algorithm uses?
A. weight, local preference, AS path, MED
B. weight, AS path, local preference, MED
C. local preference, weight MED, AS path
D. local preference, weight, AS path, MED
Answer: A
Explanation:
Path Selection Attributes: Weight > Local Preference > Originate > AS Path > Origin > MED > External
> IGP Cost > eBGP Peering > Router ID
QUESTION NO: 3
Which standard access control entry permits from odd-numbered hosts in the 10.0.0.0/24 subnet?
A. Permit 10.0.0.0.255.255.255.254
B. Permit 10.0.0.1.0.0.0.254
C. Permit 10.0.0.1.0.0.0.0
D. Permit 10.0.0.0.0.0.0.1
Answer: B
Explanation:
Remember, for the wildcard mask, 1's are I DON'T CARE, and 0's are I CARE. So now let's analyze a simple ACL:
access-list 1 permit 172.23.16.0 0.0.15.255
Two first octets are all 0's meaning that we care about the network 172.23.x.x. The third octet of the wildcard mask, 15 (0000 1111 in binary), means that we care about first 4 bits but don't care about last 4 bits so we allow the third octet in the form of 0001xxxx (minimum:00010000 = 16; maximum:
0001111 = 31).
The fourth octet is 255 (all 1 bits) that means I don't care.
Therefore network 172.23.16.0 0.0.15.255 ranges from 172.23.16.0 to 172.23.31.255.
Now let's consider the wildcard mask of 0.0.0.254 (four octet: 254 = 1111 1110) which means we only care the last bit. Therefore if the last bit of the IP address is a "1" (0000 0001) then only odd numbers are allowed. If the last bit of the IP address is a "0" (0000 0000) then only even numbers are allowed.
Note: In binary, odd numbers are always end with a "1" while even numbers are always end with a
"0".
Therefore in this question, only the statement "permit 10.0.0.1 0.0.0.254" will allow all odd- numbered hosts in the 10.0.0.0/24 subnet.
QUESTION NO: 4
Which access controls list allows only TCP traffic with a destination port range of 22-433, excluding port 80?
A. Deny tcp any any ne 80
Permit tcp any any range 22 443
B. Permit tcp any any ne 80
C. Permit tco any any range 22 443
Deny tcp any any eq 80
D. Deny tcp any any eq 80
Permit tco any any gt 21 it 444
Answer: D
QUESTION NO: 5
Which statement about multicast RPs is true?
A. RPs are required for protocol independent multicast sparse mode and dense mode.
B. By default, the RP is needed only to start new sessions with sources and receivers.
C. By default, the RP is needed periodically to maintain sessions with sources and receivers
D. RPs are required only when using protocol independent multicast dense mode.
Answer: B
Explanation:
A rendezvous point (RP) is required only in networks running Protocol Independent Multicast sparse mode (PIM-SM).
By default, the RP is needed only to start new sessions with sources and receivers.
Reference:
https://www.cisco.com/c/en/us/td/docs/ios/solutions_docs/ip_multicast/White_papers/rps.html
For your information, in PIM-SM, only network segments with active receivers that have explicitly requested multicast data will be forwarded the traffic. This method of delivering multicast data is in contrast to the PIM dense mode (PIM-DM) model. In PIM-DM, multicast traffic is initially flooded to all segments of the network. Routers that have no downstream neighbors or directly connected receivers prune back the unwanted traffic.
Microsoft MB-500J - この競争が激しい社会では、Goldmile-Infobizはたくさんの受験生の大好評を博するのは我々はいつも受験生の立場で試験ソフトを開発するからです。 Cisco 300-415J - ですから、君はうちの学習教材を安心で使って、きみの認定試験に合格することを保証します。 Amazon DOP-C02 - たくさんの時間と精力で試験に合格できないという心配な心情があれば、我々Goldmile-Infobizにあなたを助けさせます。 Goldmile-InfobizのCiscoのSAP C-CPI-2506試験トレーニング資料を手に入れたら、成功に導く鍵を手に入れるのに等しいです。 ご客様はPython Institute PCEP-30-02問題集を購入してから、勉強中で何の質問があると、行き届いたサービスを得られています。
Updated: May 28, 2022